C Programmes

Given a time in  -hour AM/PM format , convert it to military ( -hour) time. Note:  Midnight is   on a 12:00:00AM -hour clock, and   00:00:00 on a  -hour clock. Noon is 12:00:00PM  on a 12 -hour clock, and 12:00:00  on a 24 -hour clock. Input Format A single string containing a time in 12 -hour clock format (i.e.: hh:mm:ssAM  or hh:mm:ssPM  ), where   01<= hh<=12  and 00<=mm,ss<=59 . Output Format :- Convert and print the given time in 24  -hour format, where00<=hh<=23  . Sample Input 07:05:45PM Sample Output 19:05:45 #include <stdio.h> int main() { char* time = (char *)malloc(10240* sizeof(char)); scanf("%s",time); //YOUR CODE WILL BE HERE.COMPLETE THE REMAINING CODE. return 0; }

Left Rotation :- ➤ A  left rotation  operation on an array of size   shifts each of the array's elements   unit to the left. For example, if   left rotations are performed on array  , then the array would become  . ➤ Given an array of   integers and a number,  , perform   left rotations on the array. Then print the updated array as a single line of space-separated integers. ➤ FOR 4 LEFT ROTATION:- Sample Input :- 1 2 3 4 5 Sample Output :- 5 1 2 3 4 Explanation :- When we perform   left rotations, the array undergoes the following sequence of changes:- [1,2,3,4,5]->[2,3,4,5,1]->[3,4,5,1,2]->[4,5,1,2,3]->[5,1,2,3,4] Thus, we print the array's final state as a single line of space-separated values, which is  5 1 2 3 4 . Solution:-   https://drive.google.com/open?id=0B7snCzdq8oJDZUZCWkI1eXd5YUk